11.2 litre of hydrogen and 12 litre chlorine are allowed to react .after reaction find limiting reagent , excess reagent , final reagent , final composition and decrease in volume
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Answer:
The balanced equation for this reaction is :
H
2
+Cl
2
→2HCl
1 mole of H
2
reacts with 1 mole of Cl
2
to give 2 moles of HCl.
Since 22.4 litres of a gas occupies 1 mole.
Hence, moles of 12 L of H
2
will be =
22.4
12
=0.54 moles
Similarly moles of 11.2 L Cl
2
gas =
22.4
11.2
=0.5 moles
Cl
2
is the limiting reagent it is present in a limited amount.
Therefore, 0.5 moles of the Cl
2
will give 1 mole of HCl.
Since H
2
was in excess, hence some part of it is unreacted.
So moles of unreacted H
2
is
22.4
12
−
22.4
11.2
=0.035 moles
Volume of unreacted H
2
is =0.035×22.4=0.8 litres
Therefore, the composition of the volume of mixtures is 22.4 litres of HCl and 0.8 litres of H
2
.
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