Question

11.2 litre of hydrogen and 12 litre chlorine are allowed to react .after reaction find limiting reagent , excess reagent , final reagent , final composition and decrease in volume​

Answer 1

Answer:

The balanced equation for this reaction is :

H

2

+Cl

2

→2HCl

1 mole of H

2

reacts with 1 mole of Cl

2

to give 2 moles of HCl.

Since 22.4 litres of a gas occupies 1 mole.

Hence, moles of 12 L of H

2

will be =

22.4

12

=0.54 moles

Similarly moles of 11.2 L Cl

2

gas =

22.4

11.2

=0.5 moles

Cl

2

is the limiting reagent it is present in a limited amount.

Therefore, 0.5 moles of the Cl

2

will give 1 mole of HCl.

Since H

2

was in excess, hence some part of it is unreacted.

So moles of unreacted H

2

is

22.4

12

−

22.4

11.2

=0.035 moles

Volume of unreacted H

2

is =0.035×22.4=0.8 litres

Therefore, the composition of the volume of mixtures is 22.4 litres of HCl and 0.8 litres of H

2

.