Question

11 * 22 * 33 * 44 * 55 * ..1010. How many zeroes will be there at the end of a

Answer 1

Answer:

1)    A = 11 * 22 * 33 * 44 * 55 * ..... 99 * 110

      A =  11¹⁰ * 1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 10

 A zero at the end of  A appear  as many as tens in the product  PLUS the number of 2 X 5 products.   So we have  one  5   and  one 10.

  ===>  So  two zeroes for this product.

Answer 2

Answer:

2 zeros

Step-by-step explanation:

19519381200......