11,22,33. In this arthematic sequence Find 30 th term. Find algebraic form. Find sum if first 25 terms.
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First term(a) = 11
Common difference(d) = 22 - 11 = 11
Formula: nth term = a + (n - 1)d
(i): 30th term = 11 + (30 - 1)(11)
30th term = 330
(ii): Let any term be nth term = a + (n - 1)d = 11 + (n - 1)11
General term: 11 + 11n - 11
General term: 11n
Algebraic form is 11n
(iii): sum of n terms = (n/2) [2a + (n - 1)d]
Sum of 25 terms = (25/2) [2(11) + 24(11)]
Sum of 25 terms = 3575
Answered by
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First term(a) = 11
Common difference(d) = 22 - 11 = 11
Formula: nth term = a + (n - 1)d
(i): 30th term = 11 + (30 - 1)(11)
30th term = 330
(ii): Let any term be nth term = a + (n - 1)d = 11 + (n - 1)11
General term: 11 + 11n - 11
General term: 11n
Algebraic form is 11n
(iii): sum of n terms = (n/2) [2a + (n - 1)d]
Sum of 25 terms = (25/2) [2(11) + 24(11)]
Sum of 25 terms = 3575
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