Question

11,22,33. In this arthematic sequence Find 30 th term. Find algebraic form. Find sum if first 25 terms.​

Answer 1

Answer:

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Answer 2

Answer:

Hi friends

Explanation:

First term(a) = 11

Common difference(d) = 22 - 11 = 11

Formula: nth term = a + (n - 1)d

(i): 30th term = 11 + (30 - 1)(11)

30th term = 330

(ii): Let any term be nth term = a + (n - 1)d = 11 + (n - 1)11

General term: 11 + 11n - 11

General term: 11n

Algebraic form is 11n

(iii): sum of n terms = (n/2) [2a + (n - 1)d]

Sum of 25 terms = (25/2) [2(11) + 24(11)]

Sum of 25 terms = 3575