Question

(11) - 2x
alues of the following poly
(ii) 7-3a
lues of the following poly
(ii) 4 +3p-p?​

Answer 1

Step-by-step explanation:

The value of p is 3 in given polynomial function: \bold{x^{2}-2 x-(7 p+3)}x

2

−2x−(7p+3)

Given: x^{2}-2 x-(7 p+3)x

2

−2x−(7p+3) is a polynomial.

Now, we need to find the value of p.

Let, f(x)=x^{2}-2 x-(7 p+3)x

2

−2x−(7p+3)

Given that x+4 is a factor, applying f(-4) in the above equation, we get f(-4) = 0

Substitute x=-4 in the given equation,

Now we get,f(-4) = (-4)2-2(-4)-(7p+3)

On substituting the above equation, we get,16 + 8 –(7p + 3) = 0

Now, simplifying the above equation,

24 = 7p+3

7p = 21

p=3

Hence, the value of p is found to be 3, ∴p = 3