Question

11,3,17,7,29,11,?15,71 missing terms
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Answer 1

Answer:

47

Step-by-step explanation:

Answer is 47 because the numbers at odd places in the number series has a difference of the multiples of 6.

Answer 2

Step-by-step explanation:

Given:

$11,3,17,7,29,11,?,15,71$

To find:

The missing terms in the series $11,3,17,7,29,11,?,15,71$

Solution:

$11,3,17,7,29,11,?,15,71,...$

Now separate the given series into odd position alone and even position alone.

Therefore an odd position sequence is,

⇒ $11,17,29,?,71$

Here the starting number is $11$ and the next number is $17$. We start our answer from this.

Now add to $11$ by $6$ and we get $17$.

⇒ $11+6=17$

Here add to $6$ by $6$ and add it to the obtained terms.

→ $6+6=12$

⇒ $17+12=29$

Here add to $12$ by $6$ and add it to the obtained terms.

→ $12+6=18$          

⇒ $29+18=47$

∴ The missing term is $47.$

Here add to $18$ by $6$ and add it to the obtained terms.

→ $18+6=24$

⇒ $47+24=71$

and the even position sequence is,

⇒ $3,7,11,15$

Here the difference between each term goes like $+4.$

I.e. It goes like follows,

$3+4=7\\7+4=11\\11+4=15$

Now the sequence is,

$11,3,17,7,29,11,47,15,71$

Answer:

Hence the missing term in the sequence is $47.$