Physics, asked by kumaraditya75259, 2 days ago

11.3. The electrical resistance in ohms of a certain thermo-
meter varies with temperature according to the approximate
law :
R = Ro [1 + 5 x 10-8 (T-T)
The resistance is 101.6 2 at the triple point of water, and
165.52 at the normal melting point of lead (600.5 K). What is
the temperature when the resistance is 123.42 ?​

Answers

Answered by abhijeetj931
0

Answer:

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Answered by midhilaamal2010
0

Answer:

We first find α by putting the given values,

165.5=101.6(1+α(600.5−273.16))

∴α=1.92×10

−3

Now, Temp when Resistance is 123.4 is

123.4=101.6(1+α(T−273.16))

T=384.91 K

Explanation:

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