Question

11. 5 red and 8 white balls are present in a bag. If a ball is taken randomly from the bag then find the probability
of it to be
1) White ball
ii) Not to be a white ball​

Answer 1

Step-by-step explanation:

1. 8/13
2. 5/13

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Answer 2

$\huge\mathcal\color{teal} Answer:-$

Given:-

Red balls:-5 balls

White balls:-8balls

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$\huge\purple{\mid{\fbox{\tt{Find:-}}\mid}}$

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Total balls=Red balls+White balls

=5+8

=13 Balls

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$probability \: of \: white \: ball = \frac{8}{13}$

$probability \: of \: not \: \: white \: ball = 1 - \frac{8}{13}$

$\frac{1}{1} - \frac{8}{13} = \frac{13 - 8}{13} = \frac{5}{13}$

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So answers are

$so \: the \: answers \: are \: \frac{8}{13} and \frac{5}{13}$

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$\large\bf\green{Hope~it~helps}$

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