-11,-6,-1,4 .... Find the 30th terms of the arithmetic
Sequence
Answers
Answered by
4
Answer:
Given,
A1= -11
common difference, d = -6-(-11) = -1-(-6) = 4-(-1) = 5
n = 30
An = A1+(n-1)d
a30 = -11 + (30-1)5
= -11 + 29(5) = -11 + 145
a30 = 134
So, 30th term of given AP is 134
Answered by
1
Answer:
30th term is 134.
Step-by-step explanation:
a=-11, d=5
t(n)=a+(n-1) d
t(30)=-11+(30-1)×5
t(30)=-11+(29)×5
t(30)=-11+145
t(30)=134
Therefore 30th term is 134.
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