11(7y+2)/ 6y−2 = 5
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Answer:
oints) selected Mar 26, 2020 by ShasiRaj (7y + 2)/5 = (6y – 5)/11 By using cross-multiplication we get, (7y + 2)11 = (6y – 5)5 77y + 22 = 30y – 25 77y – 30y = -25 – 22 47y = -47 y = -47/47 y = -1 Let us verify the given equation now, (7y + 2)/5 = (6y – 5)/11 By substituting the value of ‘y’ we get, (7(-1) + 2)/5 = (6(-1) – 5)/11 (-7 + 2)/5 = (-6 – 5)/11 -5/5 = -11/11 -1 = -1Read more on Sarthaks.com - https://www.sarthaks.com/664513/solve-the-equationand-also-check-your-results-7y-2-5-6y-5-11?show=664517#a664517
Answer:
7y + 2)/5 = (6y – 5)/11 By using cross-multiplication we get, (7y + 2)11 = (6y – 5)5 77y + 22 = 30y – 25 77y – 30y = -25 – 22 47y = -47 y = -47/47 y = -1 Let us verify the given equation now, (7y + 2)/5 = (6y – 5)/11 By substituting the value of ‘y’ we get, (7(-1) + 2)/5 = (6(-1) – 5)/11 (-7 + 2)/5 = (-6 – 5)/11 -5/5 = -11/11 -1 = -1Read more on Sarthaks.com - https://www.sarthaks.com/664513/solve-the-equationand-also-check-your-results-7y-2-5-6y-5-11
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