11,8,5,2 in this A.Pterm. which is number -151
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aaravvarshney
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AP is 11, 8, 5, 2, …. We need to check whether – 150 is a term of AP
Lets assume it is nth term of AP
So, an = –150 Also,
a = 11, d = 8 – 11 = –3 Now,
an = a + (n – 1) d
Putting values – 150 = 11 + (n – 1) × – 3 – 150 = 11 + n (- 3) – 1 × ( – 3) – 150 = 11 – 3n + 3 – 150 = 14 – 3n – 150 – 14 = – 3n – 164 = – 3n (−164)/(− 3) = n 164/3 = n 54.33 = n
n = 54.33
Since n is coming in decimal Hence, – 150 is not term of AP.
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