Question

(11/9)^-7×(9/11)^-8​

Answer 1

$\huge\mathcal{Answer:}$

Here Both the power is Negative As We know that If powers are negative we have to reciprocal the base

But here we can see that A base is also in it's reciprocal form.

To make it easy we have to solve in this way :

$( \frac{11}{9} ) ^{ - 7} \times (\frac{9}{11}) ^{ - 8}$

$( \frac{9}{11} ) ^{7} \times (\frac{9}{11} ) ^{ - 8}$

If x is any rational number then :

$( {x})^{a} \times ({x})^{b} =( x)^{a + b}$

Taking 9/11 as x

$( \frac{9}{11} ) ^{7 + ( - 8)}$

Always Remember : + × - = -

$(\frac{9}{11}) ^{7 - 8}$

$( \frac{9}{11} ) ^{ - 1}$

$\frac{11}{9}$

Answer 2

Step-by-step explanation:

1. (9/11)^7 ×9/11^-8
2. (9/11)^7+(-8)
3. (9/11)^7-8
4. (9/11)^-1
5. 11/9