Question

(11 a + 4 b)
121a² + 88 ab + 16 b²
121 a + 88 ab + 16b²
121a² +44 ab + 16b²​

Answer 1

Answer:

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Answer 2

Answer:

STEP1:Equation at the end of step 1

((121 • (a2)) - 88ab) + 24b2

STEP 2 :

Equation at the end of step2:

(112a2 - 88ab) + 24b2

STEP3:Trying to factor a multi variable polynomial

 3.1    Factoring    121a2 - 88ab + 16b2 

Try to factor this multi-variable trinomial using trial and error 

 Found a factorization  :  (11a - 4b)•(11a - 4b)

Detecting a perfect square :

 3.2    121a2  -88ab  +16b2  is a perfect square 

 It factors into  (11a-4b)•(11a-4b)

which is another way of writing  (11a-4b)2

How to recognize a perfect square trinomial:  

 • It has three terms  

 • Two of its terms are perfect squares themselves  

 • The remaining term is twice the product of the square roots of the other two terms

Final result :

(11a - 4b)2