Question

11.
(a) 40
How many natural numbers lie between
(a) 62 and 72 (b) 192 and 202 (c) 492 and 502 (d) 752 and 762
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Answer 1

$7 containers can hold milk =\frac{101}{4} \times 7 4101​ ×7 = 176.75 litersNo. of containers required for 101 liters of milk = 4No. of containers required for 1 liter of milk =\frac{4}{101} 1014​ No. of containers required for 252.5 liters of milk = \frac{4}{101} \times 252.5 1014​ ×252.5$