Question

11. A and B together finish a work in 30 days. They worked at it for 20 days and then left
remaining work was done by A alone in 20 more days. In how many days can A alone do it​

Answer 1

Answer:

(A + B)'s 20 day's work = ( (1/30) x 20 ) = 2/3

Remaining work = ( 1 - 2/3 ) = 1 /3

Now, 1 /3 work is done by A in 20 days.

Therefore, the whole work will be done by A in (20 x 3) = 60 days.

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Answer 2

Work done by A and B together in 1 day = 1/30

A + B = 1/30 => B = 1/30 - A

A and B worked together for 20 days + A alone completed the remaining work in 20 days = whole work

(A + B )20 + (A )20 = 1

40A + 20( 1/30 – A) = 1

20A = 1 – 20/30

20A = 10/30

A = 1/60

A alone can finish the work in 60 days.


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