11. A, B, and C can do a piece of work in 10 days. A and B can do it in 12 days, A and C in 20 days. How
many days would it take each to do the work alone?
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2
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Sol:-
we can take the LCM of all 3 numbers, which ends up being 60.
we can take the LCM of all 3 numbers, which ends up being 60.A does 2 work per day, and would have 60 work completed in 602 =30 days
we can take the LCM of all 3 numbers, which ends up being 60.A does 2 work per day, and would have 60 work completed in 602 =30 daysB does 3 work per day, and would have 60 work completed in 603 =20 days
we can take the LCM of all 3 numbers, which ends up being 60.A does 2 work per day, and would have 60 work completed in 602 =30 daysB does 3 work per day, and would have 60 work completed in 603 =20 daysC does 1 work per day, and would have 60 work completed in 601 =60 day
Answered by
0
Answer:
let A = x/12
B=x/15
C= x/20
so, add three of them
x/12+x/15+x/20= 12x/60
so, x/5 left
they alone can do work in 5 days
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