Question

11. A ball is thrown vertically upwards with an initial velocity of 47 m s-1

. Calculate: (i) The maximum

height attained, (ii) The time taken by it before it reaches the ground again. (Take g = 9.8 m s-2).
​

Answer 1

Explanation:

(i)

v

2

=u

2

+2as

0=49

2

−2(9.8)(s)

s=122.5 m/s

(ii)

v=u+at

0=49−9.8t

t=5 s

total time=10 s