Question

11. A ball thrown vertically upward covers
equal distances in its fourth and fifth
second. Then initial velocity of
projection will be​

Answer 1

Answer:

Explanation:

When a ball is thrown upwards if it occupies equal distance in successive time intervals then the ball is projects up in t second reaches the maximum height and in t+1 second it returns back. So,

distance travelled in 4th second (s4) = u-(g/2)(2t-1) = u-(10/2)*(2*4-1) = u-35

distance travelled in 5th second (s5) = u-(g/2)(2t-1) = u-(10/2)*(2*5-1) = u-45

as in the fifth second the body returns back so u is -ve and g is +ve.

So, s5= -u+45

According to the question,

s4 = s5

u-35 = -u+45

u=80/2 =40m/s

Answer 2

Answer:

I donno , jp , do you have asthma