Question

11. A batsman hits boundaries for 6
times out of 30 balls. Find the
probability that he does not hit the
boundaries.
ome​

Answer 1

Given :

• A batsman hits boundaries 6 times out of 30 balls he played .

To Find :

• Probability that he does not hit the boundary .

Solution :

$\longmapsto\tt{Total\:Balls=30}$

$\longmapsto\tt{Hit\:the\:boundary=6\:times}$

Does not hit the boundary :

$\longmapsto\tt{30-6}$

$\longmapsto\tt{24\:times}$

Using Formula :

$\longmapsto\tt\boxed{Probability=\dfrac{No.\:of\:fav.\:outcomes}{Total\:no.\:of\:Outcomes}}$

Putting Values :

$\longmapsto\tt{\cancel\dfrac{24}{30}}$

$\longmapsto\tt\bf{\dfrac{4}{5}}$

So , The Probability of not hitting the boundary is 4/5 .

_______________________

Probability :

It is defined as chances of occuring or happening of an event.

• Probability of an event can never be negative.
• Probability of an event always lies between 0 and 1.

_______________________

Answer 2

• The Probability of not hitting boundaries is ${{\bold{\dfrac{4}{5}}}.}$

Step-by-step-explanation:

Given:-

• Batsman hits boundaries for 6 times out of 30 balls.

To Find:-

• The Probability that he does not hit the boundaries.

Formula used:-

• ${\boxed{\red{Probability\:=\:\dfrac{No. \:of \: Favourable\: Outcomes}{Total\:No.\:of\: outcomes}}}}$

Solution:-

No. of time he doesn't hit boundaries = 30 - 6 = 24

• No. of favourable outcomes = 24

• Total No. of outcomes = 30

Now,

$P\:=\:\dfrac{No. \:of \: Favourable\: Outcomes}{Total\:No.\:of\: outcomes}$

$P\:=\:\dfrac{24}{30}$

$P\:=\:\dfrac{4}{5}$

Hence, the Probability of not hitting boundaries is ${{\bold{\dfrac{4}{5}}}.}$

━━━━━━━━━━━━━━━━━━