Question

11. A beggar had 10 paise, 20 paise and 1Rs coins in the
ratio 10 :17 : 7 respectively at the end of the day. If
that day he earned a total of 57, then how many
20 paise coins did he have?
(b) 171
(d) 85
(a) 114
(c) 95
​

Answer 1

Step-by-step explanation:

10x*0.10 + 17x*0.20 + 7x*1.00 = 57, or

x+3.4x+7x = 57, or

11.4x = 57, or

x = 5

So he had 50 coins of 10p each, 85 coins of 20p each and 35 coins of Re.1 each.