Physics, asked by raunakm725, 8 months ago

11. A bullet of mass 10 g is fired from a rifle with a velocity of 800 m/s. after passing through a mud wall 100 cm thick, its velocity is reduced to 100 m/s. Calculate the average resistive force offered by the wall to the bullet.

Answers

Answered by TheNarayan
0

Explanation:

The resistance offered by the mud wall is 3150 N.

Explanation:

We are given:

Initial velocity or u=800m/s

Final velocity or v= 100m/s

Mass of the bullet given= 10g=0.01 kg

Distance covered by the bullet or S= 1m

We know that where a is the acceleration we need to calculate.

Substituting the values, we get:

100×100=800×800+2a  

2a= 640000-10000

We know that F=ma

=3150 N

The resistance that the mud wall offers is equal to the force =3150N

We can also calculate the resistance using the formula for kinetic energy as the resistance would be equal to the difference between the initial kinetic energy and the final kinetic energy.

We use –R because resistance is always negative)

-R= -½ (630000)  

R=3150N

I hope it helps you♥️♥️

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