Question

11 )A bullet of mass 200 g is moving with a
velocity 4 m/s. Its kinetic energy is
3.0 Marks
1.6 J
3.2 J
4.8 J
6.4 J​

Answer 1

Mass of the bullet (m) = 200 g = 0.2 kg

Velocity of the bullet (v) = 4 m/s

Kinetic Energy : It is the energy of the mass due to it's motion .

➳ It is scalar quantity

➳ SI unit is Joule

➳ K.E = ¹/₂ mv²

__________________________________________

➠ K.E = ¹/₂ mv²

➠ K.E = ¹/₂ (0.2) (4)²

➠ K.E = (0.2) (8)

➠ K.E = 1.6 J  $\pink{\bigstar}$

Option A

More Info :

⭆ Potential Energy

⭆ It is energy of the mass due to it's state/position of the object

⭆ P.E = mgH

Answer 2

Answer:

The kinetic energy of bullet is 1.6joule.

Explanation:

Given that,

• Mass of bullet (m) = 200g
• Velocity of bullet (v) = 4m/s

$:\implies$ Mass of bullet (m) = 200/1000 = 0.2 kg.

We know,

$\red \bigstar \:{ \green{ \boxed { \sf{K.E = \frac{1}{2} \times mv {}^{2} }}}}$

[ Putting values ]

$\sf : \implies \: K.E = \frac{1}{ \red2} \times \red{0.2} \times (4) {}^{2} \\ \\ \sf : \implies \: K.E = 0.1 \times 16 \\ \\ \sf : \implies \underbrace{ K.E = 1.6joule } \: \: \green \bigstar$