Question

11. A car
f mass 1000 leg accelerates uniform glom
(2 mk best to the velocity of 15 m/s in 5 second. Calulake
1. Acceleration of the ear.
2. brain in kinebir energy.
3. Average power of the engine during this time.​

Answer 1

Answer:

S=ut+21at2

=37.5 m

Force =ma

          =1000×3

          =3000 N

Power =timeWork=tForce×s

            =53000×37.5

            =22500

Gain in K.E =21m(v2−u2)

                   =21×1000(15)2

                   =112500 J

u=0,v=15 m/s

t=5 sec

a=tv−u=515−0=3 m/s2

Explanation:

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