Question

11.)A charged particle of mass 10^-14 Kg remains at rest in an electric field of intensity
2 x 10^3V/m applied vertically upwards. What is the charge on the particle?​

Answer 1

use QE=mg just plug in the values now

Answer 2

Answer:

4.9 × 10^-17 C

Explanation:

qE=mg

q=mg/E

q= 10^-14 × 10 / 2×10^3.

10/2 = 5 just cancel then

q= 10^-14 × 5 / 10^3

q= 5× 10^17 C ( 10^-14 -3 which came from denominator so it became - then ans will come 10^-17)

u can see the opt which matches is 4.9 × 10^-17

so this is ur ans

hope it helps you

All the best