Physics, asked by gurumurthid54, 8 months ago

11. A charged water drop whose radius is 0.1cm is in equilibrium
in an electric field. If charge on it is equal to charge of an
electron, then intensity of electric field will be ( g=10ms​

Answers

Answered by navdeepmatharoo20
0

Answer:

A charged water drop of radius 0.1 m is under equilibrium in some electric field. The charge on the drop is equivalent to electronic charge. The intensity of electric field is (g = 10 m/s2 )

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