Question

11. A. Compute the number of ions present in 11.7g of sodium chloride.​

Answer 1

Explanation:

58.5g of NaCl will contain one mole of sodium ions and one mole of chloride ions. So, 58.5g of NaCl contains two moles of ions in total.

Answer 2

Explanation:

NaCl-23+58.5=58.5g(Molar mass-Sum of atomic masses)

Na-23

Cl-35.5

A 58.5g NaCl contains 23 grams of Na

That is 23 in 58.5g.

Therefore X grams of Na present in 11.7g.

X in 11.7g

X/23=11.7/58.5

X=23*(11.7/58.5)=4.60g

=~0.2 mole.

HOPE IT HELPS YOU DEAR....