Question

11.A constant force acts on an object of mass 2 kg for a duration of 3 sec. This force increases the velocity of the object from 3m/s to 10m/s without change in direction. The magnitude and direction of force 14/3 N along velocity 15/3 N along velocity 24/3 N along velocity 25/3 N along veloci

Answer 1

Answer :

Mass of body = 2kg

Time of journey = 3s

Initial velocity = 3m/s

Final velocity = 10m/s

We have to find magnitude of applied force on the body$.$

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◈ As per newton's second law of motion, Force is defined as the rate of change of linear momentum.

• F = dp/dt

We know that, momentum is measured as the product of mass and velocity.

So we can say that, F = m(v - u)/dt

⇒ F = m(v - u)/dt

⇒ F = 2(10 - 3)/3

⇒ F = 2(7)/3

⇒ F = 14/3 N along velocity