Question

11. A cube of edge 5 cm is cut into cubes, each of
edge 1 cm. The ratio of the total surface area of
one of small cubes to that of the large cube is? ​

Answer 1

Answer:

Required Ratio =

$\frac{surface \: area \: of \: small \: cube}{surface \: area \: of \: large \: cube} = \\ \frac{6 \times {1}^{2} }{6 \times {5}^{2} } = \frac{1}{25}$

1 : 25

Ans.

Answer 2

Given :-

• A cube of edge 5 cm is cut into cubes, each of edge 1 cm.

To find :-

• The ratio of the total surface area of
• one of small cubes to that of the large cube

Solution :-

• Edge of cube = 5cm

As we know that

→ Total surface area of cube = 6a²

Where " a " is edge of cube .

• According to the given condition

→ Total surface area of cube

→ 6a²

→ 6 × (5)²

→ 6 × 25

→ 150 cm²

It is given that a cube of edge 5 cm is cut into cubes, each of edge 1 cm.

• Edge of small cube = 1 cm

→ Total surface area of small cube

→ 6a²

→ 6 × (1)²

→ 6cm²

The ratio of the total surface area ofone of small cube to that of the large cube

→ Total surface area of small cube/total surface area of large cube

→ 6/150

→ 3/75

→ 1/25 = 1 : 25

Hence,

• Required ratio is 1 : 25