Question

11. . A current 'I enters a uniform circular loop of radius 'R' at point M and flows out at N as
shown in the figure. Obtain the net magnetic field at the centre of the loop
90°
0

Answer 1

Answer:

0

Explanation:

Given A current 'I enters a uniform circular loop of radius 'R' at point M and flows out at N as  

shown in the figure. Obtain the net magnetic field at the centre of the loop

We know that

Magnetic field of current I1 at point O will be

B1   = μo I1 / 2 R x 1/4

Magnetic field of current I2 at point O will be  

Magnetic field of current I1 at point O will be

B2   =  μo I2 / 2 R x 3/4

Net magnetic field B = B1 + B2

                    I B I = μo I 1 / 8 R - 3μo I2 / 8 R

We know that I1 = 3 I2 (resistance of bigger part is three times that of smaller part of the loop.)

I B  I = 0  

Answer 2

Answer:

0

Explanation:

Given A current 'I enters a uniform circular loop of radius 'R' at point M and flows out at N as  

shown in the figure. Obtain the net magnetic field at the centre of the loop

We know that

The Magnetic field of current I1 at point O will be

B1   = μo I1 / 2 R x 1/4

Magnetic field of current I2 at point O will be  

Magnetic field of current I1 at point O will be

B2   =  μo I2 / 2 R x 3/4

Net magnetic field B = B1 + B2

                   I B I = μo I 1 / 8 R - 3μo I2 / 8 R

We know that I1 = 3 I2 (resistance of bigger part is three times that of smaller part of the loop.

I B  I = 0