Question

11) A cylinder contains a volume of 0.012 m' of gas at a pressure of 1.0 x 10%Pa. 400 J of work is done on this gas, with its pressure remaining constant throughout. What is the final volume of the gas? A 0.0040 m B 0.0080 m C 0.016 m D 0.020 m 3​

Answer 1

Answer:

B(  CIE physics A level paper 9702/12,February/March 2020)

Explanation:

i believe the original question is

14.A cylinder contains a volume of 0.012 m3  of gas at a pressure of 1.0 × 10^5Pa.  400 J of work is done on this gas, with its pressure remaining constant throughout.

What is the final volume of the gas?

A 0.0040 m^3   B 0.0080 m^3   C 0.016 m^3    D 0.020 m^3

explanation:

The original volumn of the the gas is 0.012m^3 and the constant gas pressure is 1.0 X 10^ 5 pa, which is 1.0 x 10^5 N/m^2.  So the initial energy the gas possesses is volumn x pressure = 0.012 x 10 ^5 = 1200 Joules. dig down to the concept, we know pressure is the force applied on one unit area( P= F/A), imagine a arrorw indicating force is squashing the cross section of the cylinder. we also know the volumn of the cylinder is cross sectional area(m^2 ) times length(m). the area cancel each other, so the result is Force x distance, which is work.

Now 400J of work is done on this gas(that should mean 400 J is done by the gas( ahhhh, English hard, i though it means done to this gas before i  read mark scheme,nvm), now, the final energy is 1200-400 = 800J. The final energy divided by the constant pressure is 800/10^5 = 0.0080 m ^3, option B.

Answer 2

Given: A cylinder contains a volume of 0.012 m³ of gas at a pressure of 1.0x10⁵ Pa. 400 J of work is done on this gas, with its pressure remaining constant throughout.

To find: The final volume of the gas.

Solution:

• Work done by an object can be calculated using the given formula.

        $W = P \delta V$

• Here, W is the work done, P is the pressure and δV is the change in volume of the gas.
• So, the equation can also be written as,

        $W = P (V_{2} - V_{1})$

• V₁ and V₂ are the volumes of the gas before and after the pressure is applied, respectively.

        $400 J = 1*10^{5} * (V_{2} - 0.012)$

        $V_{2} = 0.02 m^{3}$

Therefore, the final volume of the gas is 0.02 m³.