Question

11. A field in the form of a parallelogram has one
diagonal of 42 m long and the perpendicular
distance of this diagonal from either of the
outlying vertices is 10 m as shown in the figure
Find the area of the field​

Answer 1

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$Given :-$

A field in the form of a parallelogram has one

diagonal of 42 m long and the perpendicular

distance of this diagonal from either of the

outlying vertices is 10 m

$To \: Find :-$

$Area$

$Solution :-$

At first

Let the field be ABCD

And

Diagonal be DE and BF

Now,

Area of field = 2 × ∆ABC

$\bf \: Area = \dfrac{1}{2} \times b \times h$

$\sf \: Area = \dfrac{1}{2} \times 10 \times 42$

$\sf \: Area = 5 \times 42$

$\sf \: Area = 210 \: \: {m}^{2}$

For the field

Area = 2 × 210

$Area = 420 m²$