Question

11. A lawn of 20 m long and 7.5 m broad is to paved with tiles each measuring 3 cm by 2.5 dm.
Find the number of tiles required.​

Answer 1

Answer:

length =20m

breath=7.5m

area of laws =length *breadth

=20*7.5

=150

length equal to 3 cm equal to 0.03m

Breath equal to 2.5dm equal to 0.25m

area of 1 titles=0.03*0.25

=0.0075

number of title required equal to

total area/ area of 1 title

20 * 7.5* 10000/0.0075*10

20000 title will be required

PLZ MARK AS BRIANLIEST AND THX FOR THE SUPERB QUESTION

Answer 2

Given :-

• Length of the lawn = 20 m.

• Breadth of the lawn = 7.5 m.

• Dimension of each tile = 3 cm × 2.5 dm.

To Find :-

• Number of tiles required.

Solution :-

Converting metre to cm :-

➡  20 m

➩  20 × 100

➩  2000 cm.

➡  7.5 m

➩  7.5 × 100

➩  750 cm.

Area of the lawn :-

➩  Length × Breadth

➩  2000 × 750

➩  1500000 cm².

Area of each tiles :-

➩  3 cm × 2.5 dm

➩  75 cm².

Total Number of tiles :-

➩  Area of lawn/Area of each tiles.

➩  1500000/75

➩  20000.

∴ Number of tiles = 2000.