11. A man borrows 1000 at 10% p.a. simple interest for 3 years. He immediately lends this
money out at compound interest at the same rate for the same time. What is his gain at the
end of 3 years ?
Answers
Answered by
28
Answer:
31
Step-by-step explanation:
We know that,
SI = PRT/100.
For borrowing, P = Rs.1000, R = 10% p.a. and T = 3 years.
SI = (1000 * 10 * 3)/100
= 300
Then,
A = P + I
= 1000 + 300
= 1300
Also, It is said that:
He immediately lends this money out at compound interest at the same rate for the same time.
We know that,
A = P(1 + r/100)
For lending, P = 1000, R = 10% p.a and Time = 3 years.
A = 1000(1 + 10/100)³
= 1000(110/100)³
= 1331
Hence,
Gain = 1331 - 1300
= 31 for 3 years
Hope it helps!
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