Question

11. A man invested a sum of money in three companies A, B and C. He invested 32% of his money
in company A, 12% in company B and the rest in company C. If his investment in company C was.
A a A, B
2,10,000, then find:
a. the total money invested by the man
b. investment in company A
c.investment in company B​

Answer 1

Answer:

investment in company A = 32%

investment in company B = 12%

Investment in company C = 100% - (32+12)% = 100-44 = 56%

I. in C = 56% = 2,10,000 (given)

a. Let the total of investment money be X

X × 56/100 = 2,10,000

56X = 2,10,000 × 100

56X = 2,10,00,000

X = 2,10,00,000/56

X = 3,75,000

Rs 3,75,000 is the total money invested by the man

b. Investment in Company A =

3,75,000 × 32/100 = 1,20,000

c. Investment in Company B =

3,75,000 × 12/100 = 45,000.

Answer 2

Answer:

a= 3,75000

b=120000

c= 45,000

Step-by-step explanation: