Question

11. A man is 4 times his son's age. After 14 years, he will be twice as old as his son. Find their present age.​

Answer 1

Let

Son's age=x

Father'a Age=4x

a/q

2(x+14)=4x+14

2x+28=4x+14

14=2x

x=7

Son is 7 Years old

Father is 4x=4×7=28 years old.

Answer 2

Answer:

x = 7

4x = 4 × 7

= 28

Hope it will be helpful ✌️