Question

11. A nucleus of 84Po210 originally at rest emit alpha particle with speed v. Recoil speed of the daughter nucleus???​

Answer 1

Answer:

according to conservation of momentum, m1v1 + m2v2 = 0 m1 = mass number of α particle = 4  v1 = velocity of α particle = v  m2 = mass number of daughter nucleus = 210 – 4 = 206  v2 = velocity of daughter nucleus  ∴ 4v1 + 206v2 = 0  ∴ 206v2 = – 4v1  ∴ v2 = [(– 4v1) / (206)]  ∴ v2 = [(– 4v) / (206)] = [(4v) / (206)] (magnitude)

Explanation:

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