Question

11. A number has two digits whose sum is 9. If 27 is added to the number, its digits are reverent
then find the number.​

Answer 1

Answer:

let one digit be x

and tens digit =9-x

original no.=10(9-x)+x

=90-10x+x

= 90-9x

after adding 27

ones =9-x

tens =x

no.=10(x)+9-x

=10x+9-x

=9x+9

90-9x+27=9x-9

90+27+9=9x+9x

126=18x

x=7

ones=7

tens=2

no.=27