Question

11. A number is 6 more than two times another number. The sum of the two
numbers is 24. Find the numbers.​

Answer 1

Let the 2 numbers be x, y

$\huge{ \underline{ \sf{Given: }}} \\ \star \red{ \: \sf{ \: x = 6 + 2y}} \\ \star \pink{ \sf{ \: x + y = 24}} \\ \\ \huge{ \underline{ \sf{to \: find:}}} \\ \green{ \sf{x \: and \: y}} \\ \\ \\ \huge{ \underline{ \sf{Method : }}} \\ \\ \blue{ \sf{ using \: Substitution \: method}} \\ \\ \sf{ \purple{substitute \: Equation \: 1\: in \: Equation \: 2}} \\ \implies \sf{(6 + 2y) + y = 24} \\ \implies \orange{ \sf{6 + 2y + y = 24}} \\ \implies \sf 6 + 3y = 24 \\ \implies \sf{3(2 + y) = 3(6)} \\ \\ \sf{dividing \: by \: 3 \: on \: both \: sides } \\ ☞ \sf{2 +y = 6 } \\ \implies \sf{ y = 6 - 2 = 4} \\ \\ \therefore \boxed{ \bf{y = 4}} \\ \\ \sf{ \small{ now \: substitute \: value \: of \: y \: in \: (x = 6 + 2y)}} \\ \implies \sf{x = 6 + 2y} \\ \implies \sf{x = 6 + 2(4)} \\ \implies \sf{x = 6 + 8} \\ \implies \sf{x = 14} \\ \\ \therefore \sf{ \boxed{ \bf{x = 14}}}$