Question

11.
A particle is projected so as to just move along a vertical circle of radius r. The ratio of the tension in
the string when the particle is at the lowest and highest point on the circle is -(B)finite hut large. (C) zero
(D) Infinite​

Answer 1

Answer:

−mgcosθ=

r

mV

2

At lowest point A:

T

A

=

r

mV

A

2

+mgcos(0

o

)

⟹T

A

=

r

mV

A

2

+mg

At highest point B:

T

B

=0

∴

T

B

T

A

=

0

(mV

A

2

/r)+mg

⟹

T

B

T

A

=∞

Answer 2

Answer:

Infinite

Explanation:

at highest point, tension = 0

let tension at lowest point = $T_{a}$

ratio of the tension in  the string when the particle is at the lowest and highest point ⇒

T at lowest point/T at highest point

⇒ $T_{a}$ / 0 ⇒ Infinite

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