Question

11. A particle starting from rest undergoes a rectilinear motion with acceleration a. The variation of a with time t
is shown below. The maximum velocity attained by the particle during its motion is
10
a (m/s)
12डिस्प्लेसमेंट टाइम ग्राफ ऑफ दो मूविंग ऑब्जेक्ट ए एंड बी आर शोन इन द फिगर गिवन बिलो व्हिच ऑफ द फॉलोइंग इज करें ​

Answer 1

Answer:

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Explanation:

11.area under avst graph gives the change in velocity.  

So from give figure (graph) the change in velocity △v= area =  

2

1

​  

×base×height

△v=  

2

1

​  

×(12sec)10m/s  

2

 

△v=60m/s

​  

 

as it stated from rest so after 12 sec the  

velocity will be max=0+△v=60m/s

​  

 

after t=12 sec the acceleration will become zero  

So No more change in velocity.  

Answer 2

Answer:

60m/s

Explanation:

As area under acceleration time graph gives velocity so

1/2×b×h

1/2 ×10×12. divide 2and 10

5×12

=60 m/s

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