Question

11. A projectile is projected at an angle of 30° from the
horizontal with a velocity of 98 m/sec. Calculate (a) time
to reach the maximum height. (b) maximum height (c)
Time of flight (d) Horizontal range.
Ans. (a) 5 sec, (b) 122.5 metre. (c) 10 sec.
(d) 490/5 metre​

Answer 1

Explanation:

t=usin@/g=98×0.5/9.8=5sec

H=u^2sin^2@/2g=98×98×.25/(2×9.8)=122.5mt.

T=2t=10sec

R=u^2sin2@/g=98mt.