Question

11. A rectangular field is 15 m long and 10 m wide. Another rectangular field having the same
perimeter has its sides in the ratio 4: 1. Find the dimension of the rectangular field.
Area​

Answer 1

Answer:

hii friend here's your answer :-

4x or 4*5 = 20 m   = x or 5m

Step-by-step explanation:

Perimeter of 1st rectangle= 2(15+10)

= 2* 25

= 50 m

given, 2nd rectangle perimeter = 50 m

let the length of the 2nd rectangle be 4x and breadth be 1x or x

ATQ,

=2(4x+x) = 50

=> 2*5x = 50

=> 5x = 50/2

=> x = 25/5

=> x = 5

therefore , the dimensions of the rectangle are : length = 4x or 4*5 = 20 m

= x or 5m

Answer 2

Answer:

Dimensions are :-

• Length is 20 m.
• Breadth is 5 m.

Step-by-step explanation:

For first Rectangular field :-

Dimensions are :

Length (long) of rectangular field is 15 m

Breadth (Wide) of rectangular field is 10 m.

We know,

Perimeter of rectangle = 2(Length + Breadth)

$\longrightarrow$ 2 × (15 + 10)

$\longrightarrow$ 30 + 20

$\longrightarrow$ 50

Perimeter of field is 50 m.

For another rectangular field :-

Let Length of rectangular field be 4x

And, Breadth of rectangular field be 1x or x.

• Perimeter of first rectangular field is same as perimeter of another rectangular field.

So, Perimeter of field is 50 m.

$\longrightarrow$ 2×(4x + x) = Perimeter of field

$\longrightarrow$ 2×(4x + x)= 50

$\longrightarrow$ 8x + 2x = 50

$\longrightarrow$ 10x = 50

$\longrightarrow$ x = 50/10

$\longrightarrow$ x = 5

Dimensions :

Breadth = x = 5 m.

Length = 4x = 4×10 = 20 m.