Question

11. A rectangular plot of land is 50 m long. The cost of leveling the plot at 12.50 per
ma is 80,000. Find:
(i) the area of the plot;
(ii) the breadth of the plot;
(iii) the perimeter of the plot.
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Answer 1

Answer:

Given :

a rectangular plot of land is 50 M long the cost of the levelling the plot at rupees12.50 per metre square is 20000

To find :

find the area of the plot ,the breadth of the plot ,the parameter of the plot

Solution:

Area leveled for Rs.12.50 = 1 sq.m.

Area leveled for Rs.20000 =\frac{20000}{12.50}=1600 sq.m.

12.50

20000

=1600sq.m.

Length of plot = 50 m

Area of Plot = Length \times Breadth = 50 \times breadthLength×Breadth=50×breadth

So, 50 \times breadth = 160050×breadth=1600

Breadth = \frac{1600}{50}Breadth=

50

1600

Breadth =32

Perimeter of plot =2(l+b)=2(50+32)=164 m

Hence The area of plot is 1600 sq.m., Breadth of plot is 32 m and perimeter of plot is 164 m

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Answer 2

Answer:

$= > the \: area \: of \: rectangular \: plot = {6400}m^{2}$

$= >breath \: of \: rectangular \: plot = 128m$

$> perimeter \: of \: rectangular \: plot \: = 356m$

Step-by-step explanation:

Given that :-

A rectangular plot of land is 50 m long. The cost of leveling the plot at 12.50 per

A rectangular plot of land is 50 m long. The cost of leveling the plot at 12.50 perma is 80,000

(i) the area of the plot;

(ii) the breadth of the plot;

(iii) the perimeter of the plot.

let's find the

Area of rectangular plot:-

$\frac{tota \: cost \: of \: leveling }{cost \: of \: leveling \: plot \: at \: per \: meter}$

$\frac{80000}{12.50}$

$= > {6400}m^{2}$

$area \: of \: rectangular \: plot \: = {6400}m^{2}$

_________________________

The breadth of rectangular plot

$= > 50 \times b = 6400$

$b = \frac{6400}{50}$

$= 128$

$= > breadth \: of \: rectangular \:plot \: = 128m$

_________________________

The perimeter of the rectangular plot

The formula of perimeter = 2(l+b)

=> 2(50+128)

=> 2×178

=> 356

The perimeter of rectangular plot = 356m

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