Question

11.
A sheet of mass 20 g is kept floating horizontally in
air by firing bullets, each of mass 5 g, with the same
velocity, at the rate of 10 bullets per second and the
bullets rebound with the same speed in opposite
directions. The velocity of each bullet at the time
of impact is (Take g = 10 m s?)
A. 2 m s
B. 5 ms
C. 10 ms
D. 100 ms​

Answer 1

Answer:

hey mate your answer is...

Explanation:

m1=20g, m2=5g. ,v=10m/s

g=10ms^2

g=m1/m2*v

10=20/5*10

4=10+10

4=20

5m/s.......

OK..................

Answer 2

(A)The velocity of each bullet at the time of impact is 2 m/s.

Explanation:

Given mass of the sheet, M = 20 g = 0.02 kg.

Mass of the each bullet, m = 5 g = 0.005 kg.

The number of bullets fired per sec, n = 10.

Use the law of conservation of momentum because weight of sheet is balanced by rate change of momentum of the bullets.

Rate change of momentum of the bullets = weight of the sheet

$n(m2v)=Mg$

Here, 2v because after fired, the bullets rebound with the same speed.

Substitute the values, we get

$10\times0.005kg\times2v=0.02kg\times9.8m/s^2$

$v=1.96m/s=2m/s$.

Thus, the velocity of each bullet at the time of impact is 2 m/s.

#Learn More:

Topic: law of conservation of momentum.

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