Question

11. A snail is at rest. It accelerates at a rate of 0.00075m/s2. Calculate the time speed of 0.0135m/s​

Answer 1

Given:

• A snail starts from rest
• Acceleration of snail = 0.00075 m/s²
• Speed = 0.0135m/s

To find:

• Time taken

Solution:

Using the kinematic equation

v = u + at

Where

• v : final velocity = 0.0135 m/s
• u : initial velocity = 0 m/s.
• a : acceleration = 0.00075 m/s²
• t : time taken = ?

Here , initial velocity ( u ) = 0 m/s because the snail start from rest

Substituting the values we have

→ 0.0135 = 0 + 0.00075 × t

→ t = 0.0135/0.00075

→ t ≈ 19

Hence, time taken ≈ 19 s

★ Knowledge enhancer:

More about kinematics

Kinematics : Kinematics is a brach of mechanics which studies about the motion

Kinematic equations

1st equation : v = u + at

2nd equation : s = ut + 1/2at²

3rd equation : v² - u² = 2as

Answer 2

Given

• Initial velocity of snail = 0
• Acceleration = 0.00075 m/s²
• Final velocity of snail = 0.0135m/s

Find out

• Calculate the time taken

Solution

★ According to the first equation of motion

→ v = u + at

→ 0.0135 = 0 + 0.00075 × t

→ 0.0135 = 0.00075t

→ t = 0.0135/0.00075

→ t = 18 sec

Hence, time taken by snail is 18 sec

Additional Information

• s = ut + ½ at² {2nd equation of motion}
• v² = u² + 2as {3rd equation of motion}