Physics, asked by mcoco, 7 months ago

11
A steel tape 1m long is correctly calibrated for a temperature of 27.0 °C. The
length of a steel rod measured by this tape is found to be 63.0 cm on a hot day
when the temperature is 45.0 °C. What is the actual length of the steel rod on that
day? What is the length of the same steel rod on a day when the temperature is
27.0°C ? Coefficient of linear expansion of steel = 1.20 x 10-5 K-1

Answers

Answered by sharmaayushi41335
0

Answer:

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Answered by Harsh8557
50

Answer:

  • The actual length of the rod at 45.0</li><li>^{\circ}C is \rm{63.0136 \:cm.} It's length at 27.0^{\circ} Cis \rm{63.0 \:cm}

Explanation:

  • Length of the steel tape at temperature T = 27°C, l = 1 m (100 cm)
  • At temperature T_{1} = 45°C, the length of the steel rod, l_{1} = 63 cm
  • The Coefficient of linear expansion of steel, α = 1.20 × 10^{-5}K^{-1}
  • Let l_{2} be the actual length of the steel rod and l′ be the length of the steel tape at
  • 45°C.

Length of the steel rod measured by the steel tape at 45°C can

be calculated as:

l' = l + \alpha l (T_{1}-T)

\therefore\: l' = 100 + 1.20 \times 10^{-5} \times 100(45-27)

 = 100.0216\: cm

l_{2} = \dfrac{100.0216}{100}\times 63

 = 63.0136\: cm

Hence,

The actual length of the rod at 45.0</p><p>^{\circ}C is \rm{63.0136 \:cm}. It's length at 27.0^{\circ} Cis \rm{63.0 \:cm.}

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