Question

11. A stretched string vibrates with a frequency of 250 Hz.
If its length is increased by 25% and tension is increased
four times, what will be the new frequency of vibration
of the string?
​

Answer 1

Answer:

f=

L

T

so,

f

2

f

1

=

T

2

/

L

2

T

1

/

L

1

=

T

2

T

1

×

L

1

L

2

=

4

1

×

4

1

=

8

1

⇒f

2

=8×f

1

=8×200 =1600 Hz.

Answer 2

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