11.A tree is 50m high. Find the angle elevation of its top to a point, on the ground 100m
away from the foot of tree.
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Answer:
The angle of elevation of its top point is (θ)
The perpendicular side = AB = 50m
The base side = BC = 100m
tan(θ) = AB = 50
BC 100
tanθ = 1/2
The angle of elevation is 26.565°
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