11. a) Write the first 3 digit number which leaves a remainder 2 on division by 5
b) Which is the last such three digit number?
c) Write the sequence of three digit numbers which leaves a remainder 2 on division by 5
d) How many three digit numbers are there which leaves a remainder 2 on division by 5
Answers
Answer:
The answer of a and b part are as follows:-
a) 102
b) 997
Let first find the series of three digit natural numbers which leaves a remainder 2 when divided by 5.
So, such three digit natural numbers are
So, it means
Answer (a) First 3 digit natural number which leaves remainder 2 when divided by 5 is 102
Answer (b) Last 3 digit natural number which leaves remainder 2 when divided by 5 is 997.
Answer (c) Sequence of 3 digit natural numbers which leaves remainder 2 when divided by 5 is
Answer (d)
Since, the above sequence forms an Arithmetic Progression with
- First term, a = 102
- Common difference, d = 107 - 102 = 5
- nth term = 997
Wᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,
↝ nᵗʰ term of an arithmetic sequence is,
Wʜᴇʀᴇ,
- aₙ is the nᵗʰ term.
- a is the first term of the sequence.
- n is the no. of terms.
- d is the common difference.
Tʜᴜs,
So, it means there are 180 three digit natural numbers which leaves remainder 2 when divided by 5.
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More to Know :-
↝ Sum of n terms of an arithmetic sequence is,
Wʜᴇʀᴇ,
- Sₙ is the sum of n terms of AP.
- a is the first term of the sequence.
- n is the no. of terms.
- d is the common difference.