Question

(11): AB is the diameter. TB is tangent to the circle. If Q is a point on TB. Then QA is equal
to
"a): VAB? +4QB2
(B): V4AB2 + QB
(C): VAB2 +QB2
d): VAB2-QB2​

Answer 1

Step-by-step explanation:

From the given data , you can find the QA by applying Pythagoras theorem in it as ∠ABQ = 90 °.(The tangent is always perpendicular to the radius at the point of contact .)

QA  = √(AB2+QB2)

Hope this would have cleared your doubt .